The geometric series of $\sum _{n=0}^\infin a\cdot r^n$ or $\sum _{n=0}^\infin a\cdot r^{n-1}$
Diverges if $|r|\ge 1$.
Converges to $\frac {a_1} {1-r}$
<aside> 📌 $a_1$ is not a, it means to the first term of the series. This applied to sum where $n\ne 0$
</aside>
if $a_\infin$ is a finite number, then $S_n$ is definitely finite. (converge)
the formula for a geometric series is $S_n=a_1(\frac {1-r^n} {1-r})$ and since $r_\infin$ is approaching to a very small number (zero), the formula of a infinite geometric series is $S_\infin=\frac {a_1} {1-r}$